According to the Q equations from Rythmik, I need exactly 3 cu. ft of air surrounding the driver. Here's the math:

Total Interior Box Volume:6762.766"^3

Total Volume of Driver: 871.873"^3

Total Volume of Amp: 406.0625"^3

Total Disposable Air: 5484.8305"^3

V of Tall Brace: 263.484"^3

V of Side Brace: 277.922"^3

V of Tall Brace: 263.484"^3

V of overlap on Side Braces: 2.8125"^3

V of overlap on Tall Braces: 2.25"^3

(-) Necessary 3 Cu. Ft of air: 5184"^3

= -498.9965"^3

So,

**498.9965"^3 is the net volume of air that must be displaced**, save for the 3 calculations below (the base MDF to be removed from each Brace):

V from Tall Brace 1: 102.75"^3

V of Tall Brace 2: 102.75"^3

V of Side Brace: 190.8517"^3

This brings the total volume of MDF that

**must be removed**(after the initial removal) from the braces to:

**102.6448"^3**

## No comments:

Post a Comment