According to the Q equations from Rythmik, I need exactly 3 cu. ft of air surrounding the driver. Here's the math:
Total Interior Box Volume:6762.766"^3
Total Volume of Driver: 871.873"^3
Total Volume of Amp: 406.0625"^3
Total Disposable Air: 5484.8305"^3
V of Tall Brace: 263.484"^3
V of Side Brace: 277.922"^3
V of Tall Brace: 263.484"^3
V of overlap on Side Braces: 2.8125"^3
V of overlap on Tall Braces: 2.25"^3
(-) Necessary 3 Cu. Ft of air: 5184"^3
= -498.9965"^3
So, 498.9965"^3 is the net volume of air that must be displaced, save for the 3 calculations below (the base MDF to be removed from each Brace):
V from Tall Brace 1: 102.75"^3
V of Tall Brace 2: 102.75"^3
V of Side Brace: 190.8517"^3
This brings the total volume of MDF that must be removed (after the initial removal) from the braces to: 102.6448"^3
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